Write down the domain and the range of $g$.

Solve algebraically: $g\left(x\right)\ge -14$.

${}^{3}log\left(x\right)=2\cdot {}^{3}log\left(5\right)$

${}^{\frac{1}{3}}log\left(x\right)={}^{\frac{1}{3}}log\left(5\right)+{}^{\frac{1}{3}}log\left(2\right)$

$5-{}^{2}log\left(x\right)=0$

${}^{5}log\left(x\right)=3+4\cdot {}^{5}log\left(3\right)$

${}^{\frac{1}{3}}log\left(x\right)={}^{\frac{1}{3}}log\left(5\right)+{}^{\frac{1}{3}}log(2-x)$

${}^{5}log\left(x\right)=3+4\cdot {}^{5}log\left(x\right)$

For each function, determine the domain, the range and the asymptote.

Solve algebraically: $f\left(x\right)=g\left(x\right)$.

Solve: $f\left(x\right)\le g\left(x\right)$.

Solve: $f\left(x\right)>g\left(x\right)$.

$p=15-{}^{3}log(5-q)$

$p=600+15\cdot log\left(\frac{q}{200}\right)$